Chapter 3 · Chemistry · 7 questions in the paper · 12 min read
Organic Chemistry
What the syllabus asks for 6
- Introduction: fundamental principles, purification, nomenclature, structural isomerism, idea of reaction mechanism
- Hydrocarbons: alkanes, alkenes, alkynes, aromatic hydrocarbons
- Haloalkanes and haloarenes
- Alcohols, phenols and ethers
- Aldehydes, ketones, carboxylic acids and derivatives
- Nitro compounds and amines, aromatic and aliphatic
Organic chemistry carries about 7 of 22 questions (our estimate). The official model question "in Williamson's synthesis the haloalkane is treated with ... sodium alkoxide" shows the style: the reagent, the product or the test for a named reaction. Naming, isomer counts and acidity / basicity orders fill the rest. The six sub-areas follow one logic: what is the functional group, what attacks it, and what is formed.
- IUPAC names, structural isomer counts, electronic effects (inductive, resonance, hyperconjugation).
- Named reactions and tests: Wurtz, Markovnikov, ozonolysis, Baeyer, Lucas, Williamson, Tollens, Fehling, iodoform, Cannizzaro, aldol, Hofmann, Sandmeyer, carbylamine.
- Orders: SN1 (3° > 2° > 1°), SN2 (reverse), acidity (RCOOH > phenol > alcohol), basicity of amines, carbocation stability.
- Aromaticity (Hückel), electrophilic substitution and directing groups.
- Mole calculations: combustion, empirical and molecular formula, degree of unsaturation.
3.1 Introduction: principles, purification, nomenclature, isomerism, mechanism
Hybridisation and bonding: C in alkane sp³ (109.5°), alkene sp² (120°), alkyne sp (180°); a C–C triple bond is shortest; the % s-character (25, 33, 50) makes alkynes the most acidic hydrocarbons. Classification: acyclic / cyclic, aliphatic / aromatic, homologous series (differ by CH₂). Functional groups: –OH alcohol, –O– ether, –CHO aldehyde, >C=O ketone, –COOH acid, –COOR ester, –CONH₂ amide, –NH₂ amine, –NO₂ nitro, –X halo.
IUPAC rules: longest chain containing the principal functional group; lowest locants to the principal group, then to multiple bonds, then to substituents; alphabetical order. Priority: acid > ester > amide > aldehyde > ketone > alcohol > amine > alkene > alkyne > halide / nitro. CH₃CH(CH₃)CH₂CH₃ is 2-methylbutane; CH₃COCH₃ propanone; CH₃CH₂CHO propanal; (CH₃)₂CHOH propan-2-ol; CH₃CH=CHCH₃ but-2-ene.
Isomerism. Structural: chain, position, functional, metamerism (diethyl ether and methyl propyl ether), tautomerism. Number of structural isomers: C₄H₁₀ 2, C₅H₁₂ 3, C₆H₁₄ 5, C₇H₁₆ 9; C₂H₆O 2 (ethanol, dimethyl ether); C₄H₈ (alkenes) 3 (+2 cycloalkanes). Stereo: geometrical (cis/trans, E/Z) and optical (a chiral C has four different groups; enantiomers rotate light equally and oppositely; a racemic mixture is inactive). Degree of unsaturation =\frac{2C+2+N-H-X}{2} (benzene C₆H₆: 4).
Electronic effects: inductive (–I: NO₂, CN, halogens, COOH; +I: alkyl); resonance (+R: OH, NH₂, OR; –R: NO₂, CHO, CN); hyperconjugation (explains the stability order of alkenes and carbocations: 3° > 2° > 1° > CH₃⁺). Reagents: electrophiles (H⁺, NO₂⁺, carbocations, AlCl₃) and nucleophiles (OH⁻, CN⁻, NH₃, H₂O); free radicals; carbanions. Reaction types: substitution (SN1, SN2), addition, elimination (E1, E2; Saytzeff: the more substituted alkene), rearrangement. SN1: two steps, carbocation, racemisation, 3° > 2° > 1°; SN2: one step, inversion (Walden), 1° > 2° > 3°.
Purification: crystallisation, sublimation (naphthalene), distillation (simple, fractional, steam, vacuum), chromatography (R_f = distance of solute / of solvent). Detection (Lassaigne): sodium extract: N as NaCN gives Prussian blue, S as Na₂S gives violet with nitroprusside and black PbS, halogen as AgX (white AgCl, pale-yellow AgBr, yellow AgI). Quantitative: Dumas (N), Kjeldahl (N), Carius (halogens and S).
3.2 Hydrocarbons
Alkanes C_nH_{2n+2} (sp³, σ only): preparation by hydrogenation, Wurtz (2RX + 2Na → R–R + 2NaX; 2CH₃Br → ethane), decarboxylation (soda lime), Kolbe electrolysis. Reactions: combustion; free-radical halogenation (initiation, propagation, termination; reactivity 3° > 2° > 1° H; Cl₂ less selective than Br₂); cracking and reforming. Boiling point rises with chain length and falls with branching.
Alkenes C_nH_{2n}: dehydration of alcohols, dehydrohalogenation (alc. KOH). Electrophilic addition: Markovnikov (H adds to the carbon with more H: propene + HBr → 2-bromopropane); anti-Markovnikov (Kharasch, with peroxides, HBr only); Br₂/CCl₄ decolourised (test of unsaturation); Baeyer's test (cold dil. alkaline KMnO₄ decolourised, diol formed); hydration; ozonolysis (O₃ then Zn/H₂O: C=C → two C=O; 2-methylpropene gives acetone and formaldehyde); hydrogenation; polymerisation (polythene).
Alkynes C_nH_{2n-2}: from CaC₂ + 2H₂O → HC≡CH + Ca(OH)₂. Acidic terminal H: with ammoniacal AgNO₃ (white) / Cu₂Cl₂ (red) precipitates; hydration (Hg²⁺/H₂SO₄): ethyne → ethanal, propyne → propanone; Lindlar's catalyst gives cis-alkene, Na/liquid NH₃ gives trans; trimerisation of ethyne gives benzene.
Aromatic hydrocarbons. Benzene is planar, six π electrons, Hückel (4n+2)\pi electrons (benzene, naphthalene, the cyclopentadienyl anion; not cyclooctatetraene). It prefers electrophilic substitution: nitration (HNO₃/H₂SO₄, electrophile NO₂⁺), halogenation (Cl₂/FeCl₃), sulphonation, Friedel–Crafts alkylation and acylation (AlCl₃). Directing groups: –OH, –NH₂, –R, –X are ortho/para directors (halogens deactivate); –NO₂, –CN, –CHO, –COOH, –SO₃H are meta directors and deactivate; Friedel–Crafts fails on strongly deactivated rings. Toluene oxidises to benzoic acid.
3.3 Haloalkanes and haloarenes
Preparation: from alcohols (SOCl₂ best; HX/ZnCl₂), addition of HX, halogenation, Finkelstein (NaI/acetone). Reactions: nucleophilic substitution with aq. KOH (alcohol), alc. KOH (elimination to alkene), KCN (nitrile), NH₃ (amine), AgNO₂ (nitroalkane) vs KNO₂ (alkyl nitrite), NaOR (Williamson ether synthesis), Na (Wurtz), Mg in dry ether (Grignard reagent RMgX; with HCHO gives primary, other aldehydes secondary, ketones tertiary alcohols; with CO₂ gives acids; reacts with water to give an alkane). Reactivity R–I > R–Br > R–Cl; SN1: (CH₃)₃CBr > (CH₃)₂CHBr > CH₃CH₂Br > CH₃Br. Haloarenes are inert to SN (resonance, sp² C–X bond shorter) unless activated by ortho / para nitro groups; Sandmeyer and Fittig reactions; DDT, chloroform (CHCl₃, anaesthetic; stored in dark bottles because it forms phosgene), CCl₄, freons.
3.4 Alcohols, phenols and ethers
Alcohols. Preparation: hydration of alkenes, hydrolysis of RX, reduction of carbonyls (LiAlH₄, NaBH₄), Grignard addition. Lucas test (conc. HCl + anhydrous ZnCl₂): 3° turbid immediately, 2° in about 5 minutes, 1° only on heating. Reactions: with Na (H₂), esterification, dehydration (conc. H₂SO₄, 170 °C gives alkene; 140 °C gives ether), oxidation (1° → aldehyde (PCC) → acid; 2° → ketone; 3° resists), halide formation. Boiling points are high due to hydrogen bonding. Methanol is poisonous; ethanol from fermentation of sugar (zymase); denatured alcohol; iodoform test (I₂/NaOH, yellow CHI₃) is given by CH₃CH(OH)– and CH₃CO– groups: ethanol, propan-2-ol, ethanal, acetone — not methanol.
Phenols. More acidic than alcohols (phenoxide is resonance-stabilised) but weaker than carboxylic acids and H₂CO₃; electron-withdrawing groups raise acidity (p-nitrophenol > phenol > p-cresol > ethanol). Reactions: FeCl₃ gives a violet colour; bromine water gives white 2,4,6-tribromophenol; Reimer–Tiemann (CHCl₃/NaOH gives salicylaldehyde); Kolbe (CO₂ on sodium phenoxide gives salicylic acid, then aspirin); nitration to picric acid; coupling with diazonium salt. Phenol is made industrially from cumene.
Ethers. R–O–R′; Williamson synthesis R–X + R′ONa → R–O–R′ + NaX (best with a primary halide; tertiary halides give alkenes); low reactivity, peroxides on standing; cleaved by HI; diethyl ether anaesthetic and solvent.
3.5 Aldehydes, ketones, carboxylic acids and derivatives
Preparation: oxidation of 1° / 2° alcohols; Rosenmund (RCOCl, H₂, Pd/BaSO₄) for aldehydes; ozonolysis; Friedel–Crafts acylation for aromatic ketones; Stephen reduction. Reactions: nucleophilic addition to C=O (HCN gives cyanohydrin; NaHSO₃; Grignard; reactivity HCHO > RCHO > RCOR′ > ArCHO); condensation with NH₂OH (oxime), NH₂NH₂ (hydrazone), 2,4-DNP (orange precipitate for all carbonyls). Distinguishing tests: Tollens' (silver mirror) and Fehling's (red Cu₂O) only for aliphatic aldehydes (benzaldehyde does not respond to Fehling); iodoform for CH₃CO–; ketones are not oxidised easily. Reduction: Clemmensen (Zn–Hg/HCl) and Wolff–Kishner give CH₂; aldol condensation (needs α-H: CH₃CHO gives 3-hydroxybutanal; HCHO and benzaldehyde have none); Cannizzaro (no α-H, conc. NaOH: 2HCHO → CH₃OH + HCOONa; C₆H₅CHO → alcohol + benzoate). Formalin is 40 % HCHO.
Carboxylic acids. Acidity: HCOOH > CH₃COOH (alkyl +I weakens); –I substituents strengthen (ClCH₂COOH > CH₃COOH; CCl₃COOH very strong); benzoic acid is stronger than acetic acid. Preparation: oxidation of alcohols, hydrolysis of nitriles, Grignard + CO₂. Reactions: with NaHCO₃ (CO₂ effervescence — distinguishes acids from phenols), esterification (acid + alcohol, H⁺: CH₃COOH + C₂H₅OH ⇌ ethyl acetate + H₂O), acid chloride (SOCl₂), amide, reduction with LiAlH₄, Hell–Volhard–Zelinsky (α-bromination), decarboxylation (soda lime). Derivatives reactivity: RCOCl > anhydride > ester > amide; ester hydrolysis in base is saponification (soap); esters smell fruity. Acid anhydrides, amides (Hofmann bromamide: RCONH₂ + Br₂ + 4NaOH → RNH₂ + Na₂CO₃ + 2NaBr + 2H₂O, one carbon less).
3.6 Nitro compounds and amines
Nitroalkanes: from RX + AgNO₂; reduction gives amines; tautomerism (aci-form). Nitrobenzene: benzene + HNO₃/H₂SO₄; Sn/HCl gives aniline; in neutral medium gives phenylhydroxylamine; used for dyes.
Amines. Preparation: ammonolysis, reduction of nitro compounds / nitriles / amides, Hofmann bromamide, Gabriel (pure 1° amines). Basicity: in water the order is (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃ > C₆H₅NH₂ (aniline's lone pair is delocalised into the ring, so it is weakest). Tests: carbylamine (CHCl₃ + KOH, foul isocyanide) only for primary amines; Hinsberg (benzenesulphonyl chloride) separates 1°, 2°, 3°; nitrous acid: 1° aliphatic gives alcohol + N₂, 2° gives nitrosamine (yellow oil), 3° forms a salt; aniline + NaNO₂/HCl at 0–5 °C gives benzenediazonium chloride. Diazonium salts: Sandmeyer (CuCl, CuBr, CuCN replace N₂⁺ by Cl, Br, CN), Gattermann, replacement by OH (warm water), I (KI), H (H₃PO₂); coupling with phenol (alkaline) or aniline gives coloured azo dyes (–N=N–); aniline with Br₂ water gives 2,4,6-tribromoaniline; acetylation controls reactivity; aniline is o/p-directing, but nitration in strong acid gives meta (anilinium ion).
Markovnikov applies to HBr without peroxide only. Cannizzaro needs no α-hydrogen; aldol needs an α-hydrogen. Tollens' and Fehling's tests do not distinguish aromatic aldehydes in the same way. In aqueous basicity the tertiary amine is not the strongest. SN2 reactivity runs opposite to SN1. Acidity: look for the stability of the conjugate base.
Formula and fact sheet
| Item | Result |
|---|---|
| Wurtz | 2RX + 2Na → R–R |
| Markovnikov | H goes to C with more H |
| Lucas | 3° immediate, 2° slow, 1° heat |
| Williamson | RX + R′ONa → R–O–R′ |
| iodoform | CH₃CH(OH)– / CH₃CO– |
| Cannizzaro | no α-H; conc. NaOH |
| Hofmann | amide → amine, one C fewer |
| basicity (aq) | R₂NH > RNH₂ > R₃N > NH₃ > ArNH₂ |
| acidity | RCOOH > ArOH > ROH > HC≡CH |
| DBE | \frac{2C+2+N-H-X}{2} |
Chapter summary
- Name by the principal group; count isomers carefully (C₅H₁₂ has 3).
- Markovnikov for HX; peroxide reverses HBr; ozonolysis cuts at C=C.
- SN1 follows carbocation stability; SN2 follows steric access.
- Only carbonyls with α-H do aldol; only those without do Cannizzaro.
- Lucas distinguishes 1°, 2°, 3° alcohols; iodoform needs CH₃CH(OH)– or CH₃CO–.
- Diazotise aniline at 0–5 °C; then Sandmeyer or couple.
Practice questions
Set A — Recall (14 questions)
- The IUPAC name of CH₃CH(CH₃)CH₂CH₃ isa2-methylbutaneb3-methylbutanec2-ethylpropanedn-pentane
- The number of structural isomers of C₄H₁₀ isa1b2c3d4
- Propene reacts with HBr (no peroxide) to give mainlya1-bromopropaneb3-bromopropanec2-bromopropaned1,2-dibromopropane
- A test for unsaturation using cold dilute alkaline KMnO₄ isaTollens'bFehling'scLucasdBaeyer's
- The Wurtz reaction of methyl bromide with sodium givesaethanebmethanecpropanedethene
- Lucas reagent isaconc. HCl + anhydrous AlCl₃bconc. HCl + anhydrous ZnCl₂cconc. H₂SO₄ + ZnCl₂dHNO₃ + HCl
- In Williamson's synthesis a haloalkane is treated withaammoniabalcoholcsodium alkoxidedsilver salt of a fatty acid
- Phenol gives which colour with neutral FeCl₃?aredbgreencyellowdviolet
- Tollens' reagent gives a silver mirror withaaldehydesbketonescethersdalcohols
- The iodoform test is given byamethanolbethanolcpropan-1-oldbutan-1-ol
- Acetic acid reacts with ethanol (H⁺) to giveamethyl acetatebethyl formatecethyl acetateddiethyl ether
- Aniline with NaNO₂ and HCl at 0–5 °C givesanitrobenzenebphenolcazobenzenedbenzenediazonium chloride
- In aqueous solution the strongest base among these isa(CH₃)₂NHbCH₃NH₂c(CH₃)₃NdNH₃
- Which of these is aromatic?acyclohexanebbenzeneccyclooctatetraenedcyclohexene
Answers and explanations — Set A
1. (a) — longest chain 4 C (butane) with a methyl on C-2.
2. (b) — butane and 2-methylpropane.
3. (c) — Markovnikov: H adds to the carbon with more H.
4. (d) — Baeyer's reagent is decolourised by C=C.
5. (a) — 2CH₃Br + 2Na → CH₃–CH₃ + 2NaBr.
6. (b) — conc. HCl with anhydrous ZnCl₂.
7. (c) — R–X + R′ONa → R–O–R′ + NaX.
8. (d) — violet complex.
9. (a) — aldehydes reduce [Ag(NH₃)₂]⁺.
10. (b) — has CH₃CH(OH)–; methanol and primary alcohols other than ethanol do not.
11. (c) — CH₃COOC₂H₅.
12. (d) — diazotisation, stable only below 5 °C.
13. (a) — in water, 2° > 1° > 3° > NH₃ (solvation plus +I).
14. (b) — 6 π electrons (4n+2, n=1), planar and cyclic.
Set B — Understanding (8 questions)
- Ozonolysis of 2-methylpropene followed by reductive work-up givesatwo molecules of formaldehydebacetone and formaldehydectwo molecules of acetonedacetaldehyde and acetone
- Hydration of propyne (HgSO₄/H₂SO₄) givesapropanalbpropan-1-olcpropanonedpropanoic acid
- The compound most reactive in an SN1 reaction isaCH₃BrbCH₃CH₂Brc(CH₃)₂CHBrd(CH₃)₃CBr
- The electrophile in the nitration of benzene isaNO₂⁺bNO₂⁻cNO₂ radicaldHNO₃ molecule
- Conversion of an amide into an amine with one carbon atom less usesaLiAlH₄bBr₂ and NaOHcNaBH₄dHNO₂
- Formaldehyde with concentrated NaOH givesamethanol onlybformic acid onlycmethanol and sodium formatedCO₂ and H₂
- Which compound undergoes the aldol condensation?aHCHObbenzaldehydecCCl₃CHOdCH₃CHO
- Which is the most acidic?ap-nitrophenolbphenolcp-cresoldethanol
Answers and explanations — Set B
1. (b) — (CH₃)₂C=CH₂ gives (CH₃)₂C=O + HCHO.
2. (c) — enol CH₃C(OH)=CH₂ tautomerises to acetone.
3. (d) — tertiary carbocation is most stable.
4. (a) — HNO₃ + 2H₂SO₄ → NO₂⁺ + H₃O⁺ + 2HSO₄⁻.
5. (b) — Hofmann bromamide degradation.
6. (c) — Cannizzaro: no α-H.
7. (d) — only acetaldehyde has α-hydrogens.
8. (a) — the –NO₂ group stabilises the phenoxide by –R and –I.
Set C — Application (6 questions)
- The number of moles of water formed on complete combustion of one mole of propane isa3b4c5d8
- The percentage of carbon in methane isa80b25c75d85
- The mass of acetic acid obtained by completely oxidising 9.2 g of ethanol isa6 gb9.2 gc18 gd12 g
- A hydrocarbon contains 85.7 % C and 14.3 % H and has vapour density 28. Its molecular formula isaC₄H₈bC₂H₄cC₃H₆dC₅H₁₀
- The number of structural isomers of C₅H₁₂ isa2b4c3d5
- The degree of unsaturation of benzene (C₆H₆) isa3b5c2d4
Answers and explanations — Set C
1. (b) — C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
2. (c) — \frac{12}{16}\times100.
3. (d) — \frac{9.2}{46}=0.2 mol \times60=12 g.
4. (a) — C : H = 1 : 2, CH₂ (14); M=2\times28=56, so C₄H₈.
5. (c) — pentane, 2-methylbutane, 2,2-dimethylpropane.
6. (d) — \frac{2\times6+2-6}{2}=4 (3 C=C and 1 ring).