Matrices and Determinants

Chapter 6 · Algebra · 2 questions in the paper · 12 min read

Matrices and Determinants

What the syllabus asks for 3
  • Types, order and operations on matrices
  • Determinants, minors and cofactors
  • Adjoint, inverse and solution of linear systems

Matrices carry about two questions: the order of a matrix or a product, a 2 × 2 determinant or inverse, and one property question (singular, symmetric, effect of scalar multiplication).

The Dean's Office model asks "how many elements in a single column of a 5 × 3 matrix". Matrices are written here in rows as [[a, b], [c, d]].

What the paper asks from this chapter
  • Order and operations: m\times n, when AB exists and its order, transpose rule.
  • Determinants: ad-bc, 3 × 3 expansion, row properties, |kA|=k^n|A|.
  • Inverse: exists iff |A|\ne0; 2 × 2 formula; |A^{-1}|=\frac{1}{|A|}, |\text{adj}A|=|A|^{n-1}.
  • Linear systems: Cramer's rule and the matrix method.

6.1 Types, order and operations on matrices

  • A matrix with m rows and n columns has order m\times n and mn elements; each column has m elements.
  • Types: row, column, square, diagonal, scalar, identity I, zero (null), symmetric (A=A^T), skew-symmetric (A=-A^T, diagonal zero).
  • A+B needs equal order. AB exists only if columns of A = rows of B; order of AB is (rows of A)×(columns of B). In general AB\ne BA; AI=IA=A.
  • (A+B)^T=A^T+B^T and (AB)^T=B^TA^T.

photograph
(a) Arthur Cayley, theory of matrices (1858)
photograph
(b) J. J. Sylvester, who named the matrix
Plate 6.1. The two mathematicians who named the subject. (a) Arthur Cayley (1821-1895), who in 1858 published the first theory of matrices and proved that a matrix satisfies its own characteristic equation. (b) James Joseph Sylvester (1814-1897), who coined the word matrix in 1850 (Latin for womb or mould: a matrix produces determinants).Photo credits: (a) Herbert Beraud, Public domain; (b) Alfred Edward Emslie, Public domain.

diagram
Figure 6.1. Matrix multiplication row by column, computed. A is 2 x 3 and B is 3 x 2, so AB exists and is 2 x 2: the entry in row i, column j is row i of A dotted with column j of B, e.g. 1 x 2 + 2 x 0 + 3 x 1 = 5. Below, for two 2 x 2 matrices AB and BA differ, so multiplication is NOT commutative.

6.2 Determinants, minors and cofactors

  • For [[a, b], [c, d]], |A|=ad-bc. For a 3 × 3, expand along any row: a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13} with cofactor C_{ij}=(-1)^{i+j}M_{ij}.
  • A determinant is 0 if two rows (or columns) are equal or proportional or a row is all zero. Swapping two rows changes the sign. A triangular matrix has |A|= product of the diagonal.
  • |AB|=|A||B|, |A^T|=|A|, and |kA|=k^n|A| for order n.

diagram
Figure 6.2. What a determinant measures. The matrix M = [[3, 1], [1, 2]] sends the unit square (area 1) to a parallelogram of area |det M| = 3 x 2 - 1 x 1 = 5. A zero determinant would flatten the square onto a line, which is why such a matrix has no inverse. Right: the 3 x 3 determinant by cofactors, 2(12 - 2) - 0 + 1(1 - 3) = 18, checked with Sarrus' rule.

6.3 Adjoint, inverse and linear systems

  • A^{-1}=\frac{\text{adj}A}{|A|} exists iff |A|\ne0 (non-singular). For 2 × 2 [[a, b], [c, d]]: \text{adj}A= [[d, -b], [-c, a]].
  • AA^{-1}=I, (AB)^{-1}=B^{-1}A^{-1}, |A^{-1}|=\frac{1}{|A|}, |\text{adj}A|=|A|^{n-1}.
  • Cramer's rule for a_1x+b_1y=c_1, a_2x+b_2y=c_2: x=\frac{D_x}{D}, y=\frac{D_y}{D}, D=a_1b_2-a_2b_1, with D\ne0.

diagram
Figure 6.3. Solving 2x + y = 7, x - y = 2 with the inverse. A = [[2, 1], [1, -1]] has det = -3, adj A = [[-1, -1], [-1, 2]] (swap the diagonal, negate the off-diagonal), so A^-1 = adj A / det = [[1/3, 1/3], [1/3, -2/3]]. Then X = A^-1 B = (3, 1), checked by A x A^-1 = I with exact fractions.

diagram
Figure 6.4. A matrix is a machine that moves points. The rotation matrix R = [[0, -1], [1, 0]] turns every point 90 degrees anticlockwise: (2, 1) goes to (-1, 2) and the triangle (0,0), (2,0), (2,1) turns into (0,0), (0,2), (-1,2). The reflection [[1, 0], [0, -1]] flips it in the x-axis. Both have determinant +1 or -1, so the area (1) does not change.

6.4 Eight traps in matrices and determinants

Matrix questions reward a clear habit: check the order, then the sign, then the rule. These eight traps cover the model-paper style questions on products, determinants and inverses.

  1. Check the order before you multiply. A_{m\times n}B_{n\times p} is defined only if the columns of A equal the rows of B, and the product is m\times p (Fig 6.1). A 2\times3 times a 3\times2 gives 2\times2, but a 2\times3 times another 2\times3 is undefined. Always write the orders beside the matrices first.
  2. AB\neq BA in general. Even when both products exist they are usually different, as PQ and QP show in Fig 6.1. So (A+B)^2=A^2+AB+BA+B^2, not A^2+2AB+B^2. The reversal laws are (AB)^T=B^TA^T and (AB)^{-1}=B^{-1}A^{-1}.
  3. A zero product does not mean a zero factor. AB=0 can happen with A\neq0 and B\neq0, for example \begin{pmatrix}1&0\\0&0\end{pmatrix}\begin{pmatrix}0&0\\0&1\end{pmatrix}=0. Likewise AB=AC does not give B=C unless A is invertible. Do not cancel matrices as you cancel numbers.
  4. Only square matrices have determinants, and they obey set rules. |kA|=k^n|A| for an n\times n matrix, so doubling a 2\times2 multiplies the determinant by 4, not 2. Also |AB|=|A||B| and |A^T|=|A|. Swapping two rows changes the sign, and two equal rows give zero (Fig 6.2).
  5. Cofactor signs follow a checkerboard. The cofactor is C_{ij}=(-1)^{i+j}M_{ij}, so the signs start +,-,+ along the first row. The minor M_{ij} has no sign of its own. When expanding, pick the row or column with the most zeros, as the zero in Fig 6.2 saved a product.
  6. The adjoint is the transpose of the cofactor matrix. Many students forget the transpose. For a 2\times2 matrix the shortcut is to swap the diagonal entries and negate the other two (Fig 6.3). The key identity is A\,(\operatorname{adj}A)=|A|\,I, and |\operatorname{adj}A|=|A|^{n-1}.
  7. An inverse exists only when |A|\neq0. Then A^{-1}=\frac{\operatorname{adj}A}{|A|}, and |A^{-1}|=\frac{1}{|A|}. A matrix with determinant zero is singular and has no inverse, as when two rows are proportional. In Fig 6.2 a zero determinant would collapse the square onto a line.
  8. Solve AX=B with X=A^{-1}B in that order. Writing BA^{-1} is wrong because the product is not commutative. If |A|=0 the system has no unique solution: it has none or infinitely many. Cramer's rule gives each unknown as a ratio of determinants, x=\frac{D_x}{D}.

6.4.1 Worked checks

Q. If A=\begin{pmatrix}1&2&3\\4&5&6\end{pmatrix} and B=\begin{pmatrix}2&1\\0&3\\1&2\end{pmatrix}, find AB.

Answer. AB is 2\times2. Row 1 by column 1: 1\cdot2+2\cdot0+3\cdot1=5. Row 1 by column 2: 1+6+6=13. Row 2 by column 1: 8+0+6=14. Row 2 by column 2: 4+15+12=31. So AB=\begin{pmatrix}5&13\\14&31\end{pmatrix}.

Q. Evaluate \begin{vmatrix}2&0&1\\1&3&2\\1&1&4\end{vmatrix} and say whether the matrix is invertible.

Answer. Expand along row 1: 2(12-2)-0+1(1-3)=20-2=18. Since 18\neq0 the matrix is non-singular, so the inverse exists. Sarrus' rule gives the same value, 24+0+1-3-4-0=18.

Q. Solve 2x+y=7 and x-y=2 using the inverse.

Answer. A=\begin{pmatrix}2&1\\1&-1\end{pmatrix}, |A|=-3, A^{-1}=\frac{1}{-3}\begin{pmatrix}-1&-1\\-1&2\end{pmatrix}.

Then X=A^{-1}\begin{pmatrix}7\\2\end{pmatrix}=\frac{1}{-3}\begin{pmatrix}-9\\-3\end{pmatrix}=\begin{pmatrix}3\\1\end{pmatrix}. So x=3,y=1, which agrees with Fig 6.3.

Formula and fact sheet

Item Result
2\times2 determinant ad-bc
Product order (m\times n)(n\times p)=m\times p
(AB)^T, (AB)^{-1} B^TA^T, B^{-1}A^{-1}
\lvert kA\rvert k^n\lvert A\rvert
\lvert \text{adj}A\rvert \lvert A\rvert^{n-1}

Chapter summary

  • Order m\times n: m rows, n columns; a column holds m elements.
  • AB exists only if inner orders match, and AB\ne BA in general.
  • A zero determinant means singular: no inverse, and a row dependency.
  • |kA|=k^n|A|: the factor is raised to the order.
  • Reverse the order for (AB)^T and (AB)^{-1}.
  • Use Cramer's rule when D\ne0.

Practice questions

Set A — Recall (20 questions)

  1. A matrix of order 5 × 3 has how many elements in a single column?a5b3c4d15
  2. The determinant of [[2, 3], [1, 4]] isa11b7c5d1
  3. The product of a 2 × 3 matrix and a 3 × 4 matrix has ordera3 × 3b2 × 4c4 × 2dnot defined
  4. A square matrix whose determinant is zero is calledaidentitybsymmetriccorthogonaldsingular
  5. For a square matrix A of order n, AI equalsaAb0cIdA^2
  6. The transpose of a 2 × 3 matrix has ordera2 × 3b3 × 2c2 × 2d3 × 3
  7. (AB)^T equalsaA^TB^TbABcB^TA^TdBA
  8. The inverse of a square matrix A exists if and only ifaA is symmetricb|A|=0cA is nulld|A|\ne0
  9. If A= [[1, 2], [3, 4]] and B= [[0, 1], [1, 0]], the element in row 2, column 1 of A+B isa3b4c5d1
  10. The determinant of the 3 × 3 identity matrix isa1b0c3d9
  11. A square matrix is symmetric ifaA=-A^TbA=A^{-1}c|A|=1dA=A^T
  12. If A is 3 × 3 and |A|=2, then |2A| isa4b8c16d6
  13. The determinant of a matrix with two identical rows isa0b1c-1d2
  14. The inverse of the 2 × 2 matrix 2I isa2Ib\frac{1}{2}IcId-2I
  15. A matrix all of whose elements are zero is called aaidentity matrixbscalar matrixcdiagonal matrixdnull matrix
  16. The number of elements in a 3 × 4 matrix isa7b10c12d34
  17. The determinant of [[1, 2], [2, 4]] isa4b0c8d-4
  18. In the adjoint of [[a, b], [c, d]], the element in row 1, column 2 isa-bbbc-cdc
  19. The diagonal elements of a skew-symmetric matrix area1b-1call equaldzero
  20. |A^{-1}| equalsa|A|b-|A|c\frac{1}{|A|}d|A|^2
Answers and explanations — Set A

1. (a) — a 5 × 3 matrix has 5 rows, so each column holds 5 entries.

2. (c) — 2·4 − 3·1 = 5.

3. (b) — (2×3)(3×4) gives 2 × 4.

4. (d) — zero determinant means singular.

5. (a) — I is the multiplicative identity.

6. (b) — rows and columns swap.

7. (c) — the order reverses.

8. (d) — |A| = 0 means no inverse.

9. (b) — row 2, column 1: 3 + 1 = 4.

10. (a) — diagonal product 1·1·1.

11. (d) — (a) defines skew-symmetric.

12. (c) — 2³ × 2 = 16, not 2 × 2 = 4.

13. (a) — equal rows make the determinant vanish.

14. (b) — (2I)(½I) = I.

15. (d) — null or zero matrix.

16. (c) — 3 × 4 = 12.

17. (b) — 1·4 − 2·2 = 0, rows proportional.

18. (a) — adj has −b in the top right.

19. (d) — aᵢᵢ = −aᵢᵢ forces 0.

20. (c) — |A||A⁻¹| = |I| = 1.

Set B — Understanding (12 questions)

  1. If the determinant of [[x, 2], [3, 4]] is -2, then x isa3b2c-1d1
  2. For A= [[1, 2], [3, 4]], the element in row 1, column 1 of A^2 isa1b7c10d15
  3. For A= [[1, 2], [0, 1]] and B= [[1, 0], [3, 1]], the element in row 2, column 1 of AB isa3b7c1d0
  4. In the inverse of [[3, 1], [5, 2]], the element in row 1, column 2 isa1b5c-1d3
  5. The matrix [[k, 2], [3, 6]] is singular when k equalsa0b2c3d1
  6. If A is 3 × 3 and |A|=5, then |\text{adj}A| isa25b5c125d15
  7. If A is 3 × 2 and B is 2 × 3, the order of AB isa2 × 2b3 × 2c3 × 3d2 × 3
  8. For the system x+y=5, x-y=1, the value of x isa2b3c4d1
  9. The determinant of [[2, 5, 1], [0, 3, 7], [0, 0, 4]] isa24b14c9d0
  10. If A is 2 × 2 with |A|=3, then |3A| isa9b81c6d27
  11. The cofactor of the element in row 1, column 2 of [[1, 2], [3, 4]] isa3b-3c4d-4
  12. If [[a, 0], [0, a]] squared equals I, a possible value of a isa0b2c-1d3
Answers and explanations — Set B

1. (d) — 4x − 6 = −2, x = 1.

2. (b) — 1·1 + 2·3 = 7.

3. (a) — row 2 of A is (0, 1); column 1 of B is (1, 3); 0 + 3 = 3.

4. (c) — |A| = 1; inverse is [[2, -1], [-5, 3]].

5. (d) — 6k − 6 = 0, k = 1.

6. (a) — |A|^(3−1) = 25.

7. (c) — (3×2)(2×3) = 3 × 3, while BA would be 2 × 2.

8. (b) — adding the equations gives 2x = 6.

9. (a) — triangular: 2·3·4 = 24.

10. (d) — 3² × 3 = 27.

11. (b) — C₁₂ = −(minor 3) = −3.

12. (c) — a² = 1, so a = ±1; only −1 is listed.

Set C — Application (8 questions)

  1. Solving 2x+3y=8 and x+y=3 by Cramer's rule gives x+2y equal toa4b5c6d3
  2. If A is a 3 × 3 matrix with |A|=-2, then |A^{-1}| isa2b-2c\frac{1}{2}d-\frac{1}{2}
  3. If A= [[1, 1], [0, 1]], the element in row 1, column 2 of A^3 isa3b1c2d6
  4. The determinant of [[1, 2, 3], [4, 5, 6], [7, 8, 9]] isa1b45c0d-6
  5. For A= [[2, 1], [1, 1]], the element in row 1, column 1 of A^{-1} isa2b-1c\frac{1}{2}d1
  6. The product of [[1, 2], [3, 4]] and the column [[1], [1]] is a column whose entries add up toa7b10c3d14
  7. If the determinant of [[x, 2], [3, x]] is 3, a possible value of x isa9b6c3d0
  8. If A is the 2 × 2 matrix with a_{ij}=i+j, then |A| isa-1b1c0d17
Answers and explanations — Set C

1. (b) — D = −1, Dₓ = −1, so x = 1; y = 2 and x + 2y = 5.

2. (d) — 1/|A| = −1/2.

3. (a) — each multiplication adds 1 to the corner entry.

4. (c) — rows are in AP, so row 3 − row 2 = row 2 − row 1.

5. (d) — |A| = 1 and adj has d = 1 at the top left.

6. (b) — the column is (3, 7).

7. (c) — x² − 6 = 3 gives x = ±3.

8. (a) — [[2, 3], [3, 4]]: 8 − 9 = −1.